## Q & A: Flow Attenuation

Written by ironcore | June 28, 2012

Question:
When running an unsteady flow model with a single inflow hydrograph, why does my discharge decrease in the downstream direction for a given output profile?

This is called flow attenuation.  You see this to varying degrees in all unsteady flow models and it is a real phenomenon.  The shallower the reach, or the wider the floodplain, the more pronounced this effect will be.  In very steep streams, you may not notice flow attenuation at all.
The physical process is as follows:  As the flood level rises, water moving downstream fills in available volume.  This volume is called storage.  Water going into storage is taken away from the flow going downstream and that is why you see a decrease in discharge as you move in the downstream direction.  Wider floodplains and shallower reaches have more available storage volume, which is why flow attenuation is pronounced under these situations.  Once the flood wave passes, and you are on the receding limb of the flood hydrograph, the water that had gone into storage now returns to the active discharge.  In this case you’ll see an increase in flow as you move in the downstream direction.  Notice in the figure below that the discharge at time 0042 (before the peak of the flood wave) decreases in the downstream direction, while the flow at time 0124 (after the peak of the flood wave) increases in the downstream direction.

You can also see this effect when viewing hydrographs in the figure below from two cross sections, one upstream (River Station 2500) and one downstream (River Station 2400).  The attenuation of flow is the difference in peak discharge between these two hydrographs-in this case, about 2.3 cms.  The area between these two curves represents a volume of water.  The area to the left, where the upstream discharge is greater than that downstream discharge, represents water going into storage.  The area to the right, where the upstream discharge is less than the downstream discharge, represents water leaving storage.

Attenuation is included in the conservation of mass equation, which is one of the two equations (the St. Venant equations) used to define the movement of water through a reach in HEC-RAS-the other being conservation of momentum.    From the HEC-RAS Hydraulic Reference Manual (Page 2-22), “Conservation of mass for a control volume states that the net rate of flow into the volume be equal to the rate of change of storage inside the volume.”    In other words, Inflow minus outflow equals the change in storage over time.  The equation is:

where A = flow area, Q equals discharge, t = time, and x = length.
The discretized form of this is more practical to use and may be more familiar:

Where I = Inflow to a discrete control volume, O = Outflow, DS = Change in Storage, Dt = time duration (i.e. time step).

on February 18, 2016

Is there a recommended method for intentionally increasing attenuation? Our model shows some attenuation downstream, but not enough based on our gaged data near the downstream boundary condition.

2. ### Chris Goodell

on February 18, 2016

Increasing the n values is the easy thing to do to increase attenuation. Also, if you are not properly accounting for all available storage (both in cross sections with ineffective flow areas and offline with storage areas), you'll underestimate attenuation. Look for portions of cross sections that should be ineffective. Also, look for cross sections where the water surface extends above the end points at any time during the simulation. That is a sure way to underestimate storage.

3. ### Anonymous

on July 7, 2016

I am doing a dymamic routing of a reservoir and I would like to know how I can measure de volume of the reservoir for different levels of the reservoir.
Should I use the steady analysis or the volume of a reservoir can be obtained also using unsteady analysis.

Thanks,

4. ### Chris Goodell

on July 7, 2016

In the standard table 1 output, you can add the variable "cum volume". That is the best way to measure the volume in the reservoir. Just subtract the cumulative volume at the upstream end of the reservoir from the cumulative volume at the downstream end. If you do this from a dynamic routing run, you'll get the "dynamic" volume for a given stage. If you want a static (or level pool) volume for a given stage, set up a bunch of steady flow profiles and run those.

5. ### Angana Borah

on June 4, 2018

I am getting the same results by using breaklines and not using breaklines for a only 2d analysis. Can anyone tell me why? i have followed the standard procedure. Thanks in advance.